Question

in a cricket match , aap batsman hits a boundary 8 times out of 40 balls he played . find the probability that he didn't hit a boundary?​

Answer 1

total possible outcomes (s)

= number of balls Batman played

=40

number of favourable outcome (f)

= number of times a hits the boundary

=8

probability of hitting boundary

P(E)

= f/s

=8/40

=1/5

probability of not hitting the boundary

=1-P(E)

=1-1/5

=5-1/5

=4/5

Hence, probability of not hitting boundary= 4/5

Answer 2

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=

$probability \: that \: he \: did \: not \: hit \: a \: ball \: is \: = \frac{4}{5}$