In a cricket match, all 11 players of a team batted and the team scored 330 runs. If the first batsman scored the maximum runs and every next batsman scored 3 runs less than the previous one, how many runs did the first batsman score?
Answers
Answer:
45 Runs
Step-by-step explanation:
Given
No. of players in the team = 11
Runs scored by the whole team = 330
Let the runs scored by the first batsman be x.
Every next batsman scored three runs less than the previous man.
Let
Second Batsman Runs be x-3
Third Batsman runs be x-6
Fourth Batsman runs be x-9
Fifth Batsman runs be x-12
Sixth Batsman runs be x-15
Seventh Batsman runs be x-18
Eighth Batsman runs be x-21
Ninth Batsman runs be x-24
Tenth Batsman runs be x-27
Eleventh Batsman runs be x-30.
According to the problem,
x+x-3+x-6+x-9+x-12+x-15+x-18+x-21+x-24+x-27+x-30 = 330
11x-165 = 330
11x = 330+165
11x = 495
x = 495/11
x = 45
x = Runs scored by The First Batsman = 45.
Therefore, The Runs scored by the first batsman are 45 Runs.
Answer:
Thus the first batsman scored 45 runs .
Step-by-step explanation:
First batsman scored = x runs
Second batsman scored = x-3
Third batsman scored = x-6
Fourth Batsman scored = x-9
Now ,
x+x-3+x-6+x-9+x-12+x-15+x-18+x-21+x-24+x-27+x-30 = 330
=> 11x - 165 = 330
=> 11x = 330 + 165
=> 11x = 495
=> x = 45 runs
Thus the batsmen from first to eleventh scored 45,42,39,36,33,30,27,24,21,18 and 15 runs respectively.