Question

in a cricket match bye runs were double of the no balls the remaining score was greater by six than twelve times of bye runs if the total score was 276 how were the runs obtained

Answer 1

No balls----------x 
byes = 2x
total runs = 276 
remaining runs = (276-3x)=12*2x+6 

276-3x=24x+6 
27x=270 
x=10 
No ball
s = 10
Byes = 20
Runs = 246

Answer 2

No balls----------x 
byes = 2x
total runs = 276 
remaining runs = (276-3x)=12*2x+6 

276-3x=24x+6 
27x=270 
x=10 
No ball
s = 10
Byes = 20
Runs = 246