in a cricket match,Gaurav faces 30 balls. he hits 8 fours, 5 sixes and remaining singles in his score of 70 runs.Find probability that on playing next ball,Gaurav will (1)hit a sixer (2) make a single run (3) not be able to score
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Answered by
4
Answer:
1/6
4/15
3/10
Step-by-step explanation:
score by fours= 8*4= 32
score by sixes= 5*6= 30
score by singles= 70-30-32=8
no of dots = 30-8-5-8=9
probability of six=5/30=1/6
probability of single=8/30=4/15
probability of dot = 9/30=3/10
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Answered by
3
NO.OF BALLS=30
NO. OF SIXES=5
NO. OF FOURS=8
TOTAL SCORE=70
SO IT MEANS HE TOOK 8 SINGLES AND FACED 9 DOT BALLS
1)P(HITTING A SIXER)=NO OF SIXES/NO OF BALLS=5/30=1/6
2)P(TAKING A SINGLE RUN)=NO OF SINGLE RUNS/NO OF BALLS=8/30=4/15
3)P(NOT SCORING A RUN)=NO OF DOT BALLS/NO OF BALLS=9/30=3/10
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