Question

In a cricket match. Harbhajan took three wickets less than twice the number of wickets taken by Zaheer. The product of the numbers of wickets taken by these two is 20. Represent the above situation in the form of a quadratic equation.​

Answer 1

Let the number of wickets taken by Zahir be x.

=> Number of wickets taken by Harbhajan = 2x - 3.

According to the given condition, x(2x – 3) = 20 => 2x2 – 3x = 20 => 2x2 – 3x – 20 = 0

Therefore, the required quadratic equation is 2x2 – 3x -20=0

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Answer 2

Let the number of crickets taken by zaheer= x

Number of cricket taken by Harbhajan= 2x-3

According to question

(A.T.Q)

$x(2x - 3) = 20$

$2 {x}^{2} - 3x = 20$

$2 {x}^{2} - 3x - 20 = 0$