Question

in a cricket match if a batsman hits a boundary 4 times out of 40 balls he plays ,what is the probability that he did not hit the boundary?

Answer 1

Answer:

1/10

Step-by-step explanation:

P(E)= NO. OF FAVOURABLE OUTCOME/TOTAL NO. OF OUTCOMES

=4/40

=1/10

Answer 2

Answer:

9/10

Step-by-step explanation:

No of fav outcome=4

No of fav outcome when Batman don't hit boundary=40-4=36

Probability he didn't hit the boundary

=36/40=9/10