Question

In a cricket match karan faces 50 balls .He hits 10 fours ,5 six and remaning singles in his scores of 82 runs. Find the probability that on playing next ball he will

Answer 1

Total number of balls faced = 50 
Total number of possible outcomes = 50
It is given that he hits 10 boundaries and 5 sixes.
Number of balls in which he score boundaries = 10
Number of balls in which he scores six = 5
Total runs in boundaries and sixes = 10×4+5×6 = 40+30 = 70
Total runs scored = 82So,
 runs scored in singles = 82 − 70 = 12
Number of balls faced for singles = 12(1).
Number of balls in which he score boundaries = 10
Number of favourable outcomes = 10
P(hitting 4) = Number of favourable outcomes 

Total number of possible outcomes  = 1050 = 15(2).Number of balls in which he scores sixes=5Number of favourable outcomes = 5P(hitting 6) = Number of favourable outcomes Total number of possible outcomes  = 550 = 110(3).Number of balls in which he does not score run = 50 − (10+5+12) = 50 − 27 = 23 Number of favourable outcomes = 23P(no run) = Number of favourable outcomes.
Total number of possible outcomes  = 23/50

Answer 2

Answer:

cricketer scored a total of 62 runs in 96 balls. He hit 3 sixes, 8 fours, 2 twos and 8 singles. What percentage of the total runs came in sixes (ii) fours (iii) twos (iv) singles