in a cricket match the byes were double of the wides , and the remainder of the score was greater by three than 12 times the number of byes , if the whole score was 138 , how were the runners obtained ?
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Answer:
No balls----------x
byes = 2x
total runs = 138
remaining runs = (138-3x)=12*2x+3
138-3x=24x+3
27x=135
x=5
No ball
x= 5
Byes = 10
Runs = 123
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