Question

In a cricket match, the captain of the team played for 4 hours 28 minutes
13 seconds in the first innings and for 3 hours 49 minutes 35 seconds in the second innings. Find for how much more time he played in the first innings​

Answer 1

Answer:

1

st

Innings - 4 hrs 28 min 13 sec

2

st

Innings - 3 hrs 49 min 35 sec

So 1

st

Innings in seconds = 4 hrs=4×60=240 min

=240×60=14400 sec

28 min=28×60=1680 sec

So totally =14400+1680+13=16093 sec

2

nd

Innings in seconds :- 3 hrs=3×60×60=10800 sec

49 min=49×60=2940 sec.

So totally= 10800+2940+35=13775 sec

We have to find how much more time he played in

1

st

Innings = Total 1

st

Innings - Total 2

nd

Inning

=16093−13775=2318 sec

i.e, 1 min=60 sec

?=2318 sec ⇒

60

2318

=38.63≅39 min