Question

In a cross between individuals homozygous for (a, b) and
wild type (+, +). In this cross 700 out of 1000 individuals
were of parental type. Then the distance between 'a' and
'b' is
a. 70 map unit
b. 35 map unit
b. 30 map unit
d. 15 map unit​

Answer 1

Answer:

GIVEN:-

Cross between homozygous=(a,b)

and, wild type(A,B) or (+,+).

TOtal number of individuals= 1000.

Total parental type:- 700

so, Total recombinant type:- 300.

SO,

________________________________

R.F = total recombinant type÷ total individuals.

= 300÷1000

so,

%RF = RF×100

Hence, the distance between 'a' and 'b' is 30CM ( centi morgen) or map unit.

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Answer 2

Explanation:

The distance between a and b =

The distance between a and b = total number of offsprings/

no. of recombinants×100

no. of recombinants×100=

no. of recombinants×100= 1000/

300

300×100

300×100= 30 map units.