Question

In a cross EeFfGg×eeffGg,what will be the probability of organisms, which are homozygous for first character and heterozygous for second and third characters​

Answer 1

Cross between EeFfGg * eeffGg is mentioned in the image.

Answer 2

Homozygous for first character and heterozygous for second and third characters:

• The genes that are considered are E F and G.
• The plant with genotype EeFfGg is a pure hybrid plant with having both the dominant and recessive alleles for all three genes.
• Whereas the next plant having genotype eeffGg is a hybrid of only the third allele.
• To get the perfect genotype mixture, we will get a total of 16 different plants as there are three variables and the gene is $2^{3}$

So, the required probability comes out as $\frac{2^{2}-2}{16}=\frac{3}{16}$