In a cross hole test, the trigger and geophones are 5m apart. after impact, the arrival time of sv wave at geophone is 20 msec. the velocity of sv wave is
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t = arrival time for sv wave to reach geophone = 2 m sec = 2 x 10⁻³ sec
(since 1 milli = 10⁻³ )
d = distance between trigger and geophones = 5 m
v = speed of sv wave
the relation between speed , time and distance is given as
v = d/t
inserting the values
v = 5 m/(2 x 10⁻³ sec)
v = 2500 m/s
Answered by
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Thank you for asking this question. Here is your answer:
t = arrival time for sv wave to reach geophone = 2 m sec = 2 x 10⁻³ sec
(since 1 milli = 10⁻³ )
d = distance between trigger and geophones = 5 m
v = speed of sv wave
the relation between speed , time and distance is given as
v = d/t
inserting the values
v = 5 m/(2 x 10⁻³ sec)
v = 2500 m/s
If there is any confusion please leave a comment below.
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