Question

in a crystalline solid particle C is packed in cubic close packing particle A is at 25% of tetrahedral void and particle B is at 50% of octahedral void if the particle along one of the face diagonal are removed then simplest formula of the compound is​

Answer 1

Answer:

In the cpp arrangement the number of atoms per unit cell=4

Number of anions (C)=4

And then number of tetrahedral voids=8

Number of A atoms in the tetrahedral void is get by

=(50/100)*8

=4

Number of octahedral voids=4

Number of B atoms in octahedral voids is get by

=(50/100)*4

=2

so the formula of the solid=$A_{4} B_{2} C_{4}$