Question

in a cube Godown of length 17 metre if each box required 3.4 km of a space the boxes are placed in the room without leaving any space between them

Answer 1

Answer:

Given,

Godown length = 17m

1 m = 100 cm

Volume of godown = 1700 × 1700 × 1700

=> $4913000000 cm^{3}$

No. of cubes of $3.4 cm^{3}$

that can accommodate in the godown 

=>  4913000000 / 3.4

=>  1445000000

=>  $1445 * 10^{3}$

=> 1445000000

Or

1445 × $10^{6}$  cubes can be placed in the godown

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@GauravSaxena01