In a cubic unit cell A atoms are at the corner, B atoms are at the face centre ,C atoms are at edge centre and D atoms are at body centre . If 25% of A,50% of B,75%of C is removed then calculate the molecular formula
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Answer:
Initially, atoms effectively in the lattice are as follows:
A→8×
8
1
,B→6×
2
1
,C→1,D→12×
4
1
After the removal of atoms,
atoms left at the corners=8−4=4⇒A→4×
8
1
=
2
1
atoms left at the face center=6−2=4⇒B→4×
2
1
=2
atoms left at the body center=0⇒C→0
atoms left at edge center=12−2=10⇒D→10×
4
1
=2.5
ratio of A:B,C:D=0.5:2:0:2.5=1:4:0:5
Hence, compound formula is AB
4
D
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