Question

In a cuboidal box 30 cm x 20 cm x 10 cm, how many cubes of 5 cm length each can be arranged?

Answer 1

Total number of cubes = (30×20×10)/(5×5×5) = 48

Answer 2

Answer:

48

Step-by-step explanation:

As per the question,

Given a cuboidal box having dimensions 30 cm x 20 cm x 10.

That is,

Length = 30 cm

Breadth = 20 cm

Height = 10 cm

As we know that volume of the cube is given by formula,

V = l × b × h

∴ Volume of cuboidal box =  l × b × h

= 30 cm x 20 cm x 10

= 6000 cm³

Now,

Smaller cube of side = 5 cm

∴ Volume = 5 × 5 × 5 = 125 cm³

Let the total number of small cube = n

∴ Total volume = 125n =6000

125n = 6000

n =  48

Hence, number of small cubes that can be arranged = 48.