Question

In a current carrying conductor the net charge is 1.6 into 10 ki power 19 column a number 20 6.25 into 10 power minus 18 column number de zero and number Infinity solution

Answer 1

Answer:

I=

t

Q

⇒1A=

1s

Q

⇒Q=1C

Now, charge of one electron is 1.6×10

−19

coulombs

Therefore, in 1 coulomb charge, number of electrons =

1.6×10

−19

1

=0.625×10

19

=6.25×10

18

electrons