Question

In a cycle race a cyclist beginning from the starting point attains a velocity of 5m/s in

30s .Assuming that the acceleration is uniform ,find the distance travelled by the cyclist

for attaining this velocity.​

Answer 1

Answer:

Initial velocity = 0m/s

Final velocity= 5m/s

Time= 30s

Distance travelled=S=?

Know

vf=vi+at

a=vf-vi/t

a=5-0/30

a=0.16 m/s^2

know

S = Vit + 1/2at2

S=0*30+1/2(0.16)(30)^2

S=0+1/2(0.16)(900)

S=0+1/2 (144)

S=0+72

S=72m

so distance travelled is 72 meters.

Explanation:

this problem is solved by 1st and 2nd equation of motion.

which are given as

FIRST EQUATION OF MOTION

Vf = Vi + at

SECOND EQUATION OF MOTION

S = Vit+ 1/2 a t^2

Answer 2

Answer:

The distance travelled by the cyclist = S =150 m

Explanation:

velocity = v =5m/s

time = 30 sec

since,

V = S/t

S= V*t

S= 5(30)

S= 150 m