Science, asked by Vivekvijay026, 9 months ago

In a cyclic heat engine operating between a source temperature of 1050 K and a sink temperature of 300 K, the least rate of heat rejection per kW net output of the engine is

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Answered by wwwseenalingampalli
2

Explanation:

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Answered by Anonymous
0

Heatabsorption = (T₁-T₂) / T₁

= (873 - 293) / 873

= 0.664

∴HeatRejected = 1 − heatabsorbed

=1 − 0.664

∴Heatrejected=0.335

Hence the heat of rejection per kW is 0.335

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