In a cyclic heat engine operating between a source temperature of 1050 K and a sink temperature of 300 K, the least rate of heat rejection per kW net output of the engine is
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Heatabsorption = (T₁-T₂) / T₁
= (873 - 293) / 873
= 0.664
∴HeatRejected = 1 − heatabsorbed
=1 − 0.664
∴Heatrejected=0.335
Hence the heat of rejection per kW is 0.335
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