in a cyclic quadrilatel ABCD, angle (A=x+2y+7)°, angle B=(2x+y+7)°, angle C=(4x+y+3)°and angle D=(4x+8)°. find for angle
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Step-by-step explanation:
Given
A = x+2y+7
B = 2x+y+7
C = 4x+y+3
D = 4x+8
Formula used
sum of angles of a quadilateral = 360
Solution
x+2y+7+2x+y+7+4x+y+3+4x+8 = 360
11x+4y+25 = 360
11x+4y = 360-25 = 335
11x+4y = 335
Also,
B+D = 180
6x+y+15 = 180
6x+y = 180-15 = 165
6x+y = 165
By solving these two equations you will get the values of x and y
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