Question

In a cyclic quadrilatera PQRS, angle p and angle R are opposite vetices. If p is 60° more than R , find <pand <R​

Answer 1

Step-by-step explanation:

p + r = 180°

60 + r = 180

r = 120°

Answer 2

Theory:-

Sum of opposite angles of a cyclic quadrilateral are 180°.

Solution:-

Let, the value of ∠R be x°

Then, the value of ∠P = 60° + x°

Also, ∠R and ∠P are opposite angles of a cyclic quadrilateral.

So,

x° + (60° + x°) = 180°

or, 2x° = 120°

or, x° = 60°

Hence, the value of ∠R = 60°

&, the value of ∠P = 60° + 60° = 120°

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