in a cyclic quadrilateral ABCD 5angleA=13 angleC find angle A
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Step-by-step explanation:
In cyclic quadrilateral sum of opposite angles is 180
−4x+4y+20=180⟹y−x=40
y=40+x
−7x+5+3y−5=0
7x−3y+180=0
7x−3(40+x)+180=0
4x+60=0
x=−15 ⟹y=25
∠A=4(25)+20=120
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