Math, asked by gayatrirajput125, 18 days ago

In a cyclic quadrilateral ABCD, AB||CD. If ∆B= 80° then find the remaining angles of ABCD.​

Answers

Answered by Mysteryboy01
3

∠B+ ∠D = 180°

80°+ ∠D = 180°

∠D = 180°- 80°

∠D =100°

AB||CD \:  \:  \:  \: so \:

∠B+ ∠C = 180°

80°+ ∠C = 180°

∠C= 180°- 80°

∠C =100°

∠a+ ∠C = 180°

∠A+110°=180°

∠A = 180°- 110°

∠A = 70°

Answered by ParikshitPulliwar
0

Answer: we know that,in a cyclic quadrilateral,

opposite angles are supplementary.

therefore m<C = 180-80= 100°

Step-by-step explanation:

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