in a cyclic quadrilateral ABCD /ABC 105° then find ADC
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In cyclic quadrilateral ABCD
ABC+ADC= 180
105+ADC=180
ADC=180-105
ADC=75
ABC+ADC= 180
105+ADC=180
ADC=180-105
ADC=75
maths157:
right hai kya
Answered by
1
Heya buddy,
Here is your answer,
Well since, ABCD is a cyclic quadrilateral,
Thus,
The sum of the opposite angles of a cyclic quadrilateral is equal to 180°
Thus,
In cyclic quadrilateral ABCD,
Angle(ABC) = 105° (given)
Angle(ADC) = ?
Therefore,
=> Angle(ABC) + Angle(ADC) = 180°
=> Angle(ADC) + 105° = 180°
=> Angle(ADC) = 180° - 105°
=> Angle(ADC) = 75° (ANS)
Hope it helps you.
Thank you.
Also pls do add it as brainliest if u liked it.
Here is your answer,
Well since, ABCD is a cyclic quadrilateral,
Thus,
The sum of the opposite angles of a cyclic quadrilateral is equal to 180°
Thus,
In cyclic quadrilateral ABCD,
Angle(ABC) = 105° (given)
Angle(ADC) = ?
Therefore,
=> Angle(ABC) + Angle(ADC) = 180°
=> Angle(ADC) + 105° = 180°
=> Angle(ADC) = 180° - 105°
=> Angle(ADC) = 75° (ANS)
Hope it helps you.
Thank you.
Also pls do add it as brainliest if u liked it.
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