Question

in a cyclic quadrilateral ABCD If angle A-Angle c=60degree prove that the smaller of two is 60 degree

Answer 1

angle A +anglec=180degrees

let the smaller angle C be x and the bigger angle be 180-x

180-x-x=60

180-2x=60

2x=180-60

2x=120

x=60degrees

i hope this is helpfull

Answer 2

Answer:

Here is your answer......

Step-by-step explanation:

Since, B + D = 180°

[Sum of opposite angles of a cyclic quadrilateral]

B- D= 60°