In a cyclic quadrilateral ABCD, if angle B - angle D is 60°. Then angle D =
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Answered by
0
Answer:
Solution–
Angle B - Angle D = 60°
Angle D = 60° + Angle B
Step-by-step explanation:
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Answered by
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Answer: (∠B−∠D)=60
o
.(1)
(∠B+∠D)=180
o
(2)
By adding both the equations
∠B−∠D+∠B−∠D=60
+180
So we get
2∠B=240
By division
∠B=120
By substituting equation it in equation (1)
(∠B−∠D)=60
120
−∠D=60
On further calculation
∠D=120
−60
by subtraction
∠D=60
Therefore, the smaller of the two angles ∠D=60
Step-by-step explanation:
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