In a cyclic quadrilateral ABCD , it is being given that angle A = (x+y+10) degree , angle B = (y+20) degree , angle C = (x+y-30) degree and angleD = ( x+y) degree. Then angle B = ?
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1
Step-by-step explanation:
As ABCD is a cyclic quadrilateral, we have
∠A+∠C=180
o
6x+10
o
+x+y=180
o
7x+y=170
o
.....(1)
and ∠B+∠D=180
o
(3y−10)+5x=180
o
3y+5x=190 ....(2)
Solving (1) and (2), we have
x=20
o
y=30
o
A=6x+10=6×20
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+10
o
=130
o
B=5x=5×20
o
=100
o
C=x+y=30
o
+20
o
=50
o
D=3y−10=3×30−10=80
o
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anwer is 80°
hope it helps you
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