In a cyclic quadrilateral ABCD, m∠CAB=45 and m∠ABC=100, then m∠ADB = ______ .
(a) 55
(b) 105
(c) 80
(d) 35
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Answer:
∠ ADB = 35°
Step-by-step explanation:
We have given a cyclic quadrilateral,
m∠CAB=45° and m∠ABC=100°
We have to find m∠ADB
Make a circle. Draw a cyclic quadrilateral and name it ABCD than Join AC and BD.
In ∠ABC
m∠CAB=45° and m∠ABC=100°
By angle sum property,
∠CAB + ∠ACB + ∠ABC = 180°
45° + ∠ACB + 100° = 180°
∠ACB = 180° - 145° = 35°
∠ACB = 35°
We get angle ∠ACB = 35°
∠ACB = ∠ADB,
(As the are angles subtended by the same chord on the same side of the chord)
Therefore, ∠ADB = 35°
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