Question

In a cyclic quadrilateral ABCD, ZA:2 C = 4:5 and
ZB: D = 5:7, then find all the angles of ABCD​

Answer 1

Step-by-step explanation:

Angle A:C=4:5

So, Let angle A be 4x and C be 5x

5x+4x=180

9x=180

x=20

Angle A=80 and C=100

In the same way

Let angle B be 5y and D be 7y

5y+7y=180

12y=180

y=15

Angle B=45 and D=105