In a cyclic quadrilateral angle AOB is 70° find angle ADC and angle ACB answer fast
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Construction: Join B and D. This forms a right triangle ADB.
From the figure, we can say that angle B is 50 deg [opposite angles in a cyclic quadrilateral are supplementary]
Consider triangle ACB.
Angle ACB is 90 deg [ angle in a semicircle is 90 deg]
Angle ABC is 50 deg
So, angle BAC is 40 deg [angle sum property of a triangle].
Angle BAC is 40 deg.
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