Question

In a cyclic quadrilateral if ∠B - ∠D = 60º, then the smaller of the angles B and D is :

Answer 1

Answer:

Step-by-step explanation:

if the quadrilateral is cyclic then

<B + <D= 180º

And given

<B - <D=60º

Therefore from these equations we get <B=120º & <D=60º

Hence <B is greater than <D