Question

In a cyclic quadrilateral PQRS, 5 angle Q= 7 angle S, then find angle Q.
The answer should be 105 degree.
Please fast!!

Answer 1

angel Q+angel R=180°

let angel Q and S be 7x and 5x

now ,7x+5x=180°

12x=180°

x=180/12

x=15°

angle Q=15^7=105°

Answer 2

Given :

5∠Q =7∠S

To find :

Angle Q

Solution :

• ∠S = 5∠Q/7

• Sum of opposite angles in a quadrilateral is 180°

      ∠Q+∠S = 180°

• By substituting the value of ∠S

      Q + (5Q/7) = 180

      12Q = 180×7

      Q = 180×7 / 12

      Q=105°

• The value of angle Q=105°