in a cyclic quadrilateral pqrs 5 angle Q = 7 angle S then find angle Q
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angel Q+angel R=180°
let angel Q and S be 7x and 5x
now ,7x+5x=180°
12x=180°
x=180/12
x=15°
angle Q=15^7=105°
let angel Q and S be 7x and 5x
now ,7x+5x=180°
12x=180°
x=180/12
x=15°
angle Q=15^7=105°
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angle Q=15^7=105° see my answer is right
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