in a cyclic quadrilateral pqrs 5 angle Q = 7 angle S then find angle q
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in a cyclic quadrilateral, sum of opposite angles = 180°
angle Q + angle S =180° -----(1)
multiply the equation by 7
7(angleQ) + 7(angle S) = 180°×7 ----(2)
given= 5 angle Q = 7 angle S
substitute the given condition in equation 2
7 angle Q+ 5 angle Q = 1260°
12 angle Q = 1260°
angle Q = 1260°/12
angle Q = 105°
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