In a cyclic quadrilateral pqrs if angle p - angle r =50, angle p and angle r
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Since quadrilateral PQRS is a cyclic
Therefore, Angle P+ Angle R = 180..... Opposite Angle are supplementary
Therefore, Angle P + 50 = 180
Therefore, Angle P = 180 - 50
Therefore, Angle P = 130
Angle P = 130
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Therefore, Angle P+ Angle R = 180..... Opposite Angle are supplementary
Therefore, Angle P + 50 = 180
Therefore, Angle P = 180 - 50
Therefore, Angle P = 130
Angle P = 130
Pls mark me as brainlist
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