Question

. In a cyclic quadrilateral PQRS, if < P−< R = 50°, then find ​

Answer 1

step by step explanation

by given cordinate

p+r=180

second cordinate

p-r=50

put p=180-r in p-r=50

180-r-r=50

130=2r

r=65

p=180-65

p=115

Answer 2

Answer:

Given :-

<P - <R = 50

Also PQRS is a cyclic quadrilateral. So,

<P + <R = 180

Subtracting Equation 1 from 2

<P + <R - <P + <R = 180 - 50

<R + <R = 130

2<R = 130

<R = 65°

<P - <R = 50

<P = 50 + <R

<P = 50 + 65

<P = 115°

Therefore,

<P = 115°

<R = 65°