In a cyclic quadrilateral,the angles A,B,C and D are (2x+4),(x+10),(4y-4) and (5y-5) respectively.Find the values of x and y. URGENT please hlp!!!
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A=2x+4,B=x+10,C=4y-4,D=5y-5
given ABCD is cyclic Quadrilateral
sum of opposit angles are supplementary
A+C=180
2x+4+4y-4=180
2x+4y=180
x+2y=90----(1)
B+D=180
x+10+5y-5=180
x+5y=180-10+5
x+5y=175-----(2)
sutract (1) from (2)
3y =85
y= 85/3
Substituting y= 85/3 in (1)
x+2*85/3=90
x=90-170/3
x=(270-170)/3
x=100/3
substitute x and y in A,B,C,D you can get all angles
given ABCD is cyclic Quadrilateral
sum of opposit angles are supplementary
A+C=180
2x+4+4y-4=180
2x+4y=180
x+2y=90----(1)
B+D=180
x+10+5y-5=180
x+5y=180-10+5
x+5y=175-----(2)
sutract (1) from (2)
3y =85
y= 85/3
Substituting y= 85/3 in (1)
x+2*85/3=90
x=90-170/3
x=(270-170)/3
x=100/3
substitute x and y in A,B,C,D you can get all angles
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