Question

in a cyclic quadrilateralLVNM, angle L=7x+1, angleV=2x+100, angleN= 2y+74, angle M=6x-10​

Answer 1

Answer:

in a cyclic quadrilateral the sum of opposite angles is 180

(7x+1)+(2y+74)=180

7x+1+2y+74=180

7x+2y=180-75

7x+2y=105---(1)

(2y+100)+(6x-10)=180

2y+100+6x-10=180

2y+6x=180-90

2y+6x=90

6x+2y=90---(2)

on subracting equation (2) from (1), we get

7x+2y=105

6x+2y=90

x=15

put x=15 in equation (1)

7(15)+2y=105

105+2y=105

2y=105-105

2y=0

y=0/2

y=0

theredore,x=15,y=0