Math, asked by shuva8a, 5 months ago

In a cyclic trapezium ABCD, in which AB || DC diagonals AC and BD intersect at P. Show that
PA = PB and PC = PD.

Answers

Answered by km9505946

0

Step-by-step explanation:

well I don't know it is correct or not but I tried my level best

hope it will help you

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