Math, asked by sharmarajat79805, 8 months ago

in a cyclic trapezium ,the non-parllel sides are equal and diagnosis are also equal .prove it​

Answers

Answered by InFocus
0

Answer:

Answer :- Let ABCD be the cyclic trapezium in which AB||CD.

We have to prove that AD = BC

Since AB||CD and BD is the transversal, we have

∠ABD = ∠BDC [Alternate angles]

Also chord AD subtends ∠ABD and chord BC subtends ∠BDC on the circle at B and D respectively.

Also ∠ABD =∠BDC (proved above)

Therefore, AD = BC

Step-by-step explanation:

Attachments:
Similar questions