Question

in a cyclotron for a given magnet radius of the semicircle traced by positive ion is directly proportional to​

Answer 1

Answer:

r is directly proportional to v

Explanation:

When a positive ion traces a semicircle, the centrifugal force acting on the particle is balanced by the magnetic force i.e. Fcentrifugal​=Fmagnetic​

rmv2​=qvB

⟹ r=qBmv​

We get, r∝v

Answer 2

Answer:

r ∝ v

Explanation:

In a cyclotron, for a given magnet the centripetal force traced by the semicircle will be equal to magnetic force,

F(centripetal) = F(magnetic)

$\sf{\dfrac{mv^2}{r}}$ = qvB

$\sf{r = {\dfrac{mv}{qB}}}$

r ∝ v

• v = velocity of the particle