Question

In a cylinder , if radious is halved and height is doubled then the volume will be

Answer 1

remain unchanged..................................................
π rsquare h
π rsq./2×2h
π rsq.h

Answer 2

Hey friend, Harish here.

Here is your answer:

We know that,

⇒ $Volume\ of\ cylinder = \pi r^{2} h$    - (Original Volume)

After some changes: 

$New\ radius = \frac{r}{2} \\ \\ Height = 2h$

Then,

⇒ $New\ volume = \pi \times ( \frac{r}{2})^{2} \times (2h)$

⇒ $\pi \times ( \frac{r^{2}}{4}) \times 2h = \frac{1}{2} \times ( \pi {r^{2} h)$

Now by comparing we know that;

⇒ $New\ volume = \frac{1}{2} \ of\ Original\ Volume$

Therefore the volume is reduced by half.
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Hope my answer is helpful to you.