Question

In a cylinder,if radius is halved and height is doubled, what will be it's volume​

Answer 1

Step-by-step explanation:

volume- πr²h

π(r/2)²2h

π×r²/4×2h

π r²/2 h

πr²h/2

Answer 2

Answer:

the answer is - The Volume gets halved.

Step-by-step explanation:

for instance, lets take

original Radius= 2r

and Original height = h

So, the Original volume of the cylinder becomes=

π(2r)²h

or, π4r²h

or, 4πr²h

Now,

The original radius gets halved that is

2r /2 = r

∴ r is the new radius

And,

the Original Height gets doubled that is

h × 2 = 2h

∴ 2h is the new height

so the new volume becomes

πr²(2h)

or 2πr²h.

Now Lets compare both the Volumes..

Let Original Volume be V1

and the new volume be V2

∴ V1 / V2 = 4πr²h / 2πr²h

⇒ V1/V2 = 4/2                                    (∵ πr²h gets cancelled)

⇒V1/V2 = 2/1

By Cross Multiplying,

⇒V1= 2V2

⇒V1/2 = V2

clearly 1/2 ×V1 = V2

so the new volume is half of the original volume

So The VOLUME GETS HALVED.

This is the first time I answered a Question.. Hope it was clear

Thanks :)