In a cylinder, if radius is halved and the height is doubled then find its curved surface area.
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Answered by
3
let the radius be r and height be h
volume = \pi r^{2} hπr2h
if the radius is halved then radius = r/2
and height is doubled ,so height= 2h
volume =[\pi r*r/4*2hπr∗r/4∗2h
= \pi *r ^{2} *h/2π∗r2∗h/2
hence the volume will be halved
volume = \pi r^{2} hπr2h
if the radius is halved then radius = r/2
and height is doubled ,so height= 2h
volume =[\pi r*r/4*2hπr∗r/4∗2h
= \pi *r ^{2} *h/2π∗r2∗h/2
hence the volume will be halved
Answered by
0
Answer:the same
Step-by-step explanation:
2×22/7×r×h
Is the formula
Now,
2×22/7×r/2×h×2
2 and 2 getscancelled
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