in a cylinder its radius is halved and height is doubled then find the ratio of volume of original to new one.
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Original Volume of cylinder= 22/7 x r^2 x h
when radius= r/2 and height= 2h
then new volume= 22/7 x (r/2)^2 x (2h)
Original volume/ new volume= 2
therefore when radius is halved and height is doubled then the new volume becomes 1/2 times of the original volume.
Answered by
1
Volume of a cylinder = r²h
original volume = r²h
new radius =r/2
new height =2h
mew volume = (r/2)² × 2h
= r²/4 × 2h
= r²/2 × h
Volume of original cylinder : volume of new cylider = r²h: r²/2 × h
=r² : r²/2 ( and h cancelled)
Multiplying by 2
= 2r² : r² (r² cancelled)
= 2
original volume = r²h
new radius =r/2
new height =2h
mew volume = (r/2)² × 2h
= r²/4 × 2h
= r²/2 × h
Volume of original cylinder : volume of new cylider = r²h: r²/2 × h
=r² : r²/2 ( and h cancelled)
Multiplying by 2
= 2r² : r² (r² cancelled)
= 2
bleszzzz:
Nice answer
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