Question

In a cylinder, r= 14 and LSA = 280r. Find the height and volume of the cylinder​

Answer 1

Step-by-step explanation:

• LSA =2πrh
• 280=2×22/7×14×h
• 280=88×h
• 280/88=h
• h=35/11
• volume
• πr square h
• 22/7×14×14×35/11
• 21560/11
• 1960

Answer 2

Answer:

Given : r = 14

Given : r = 14 LSA = 280π

Given : r = 14 LSA = 280πsolution:

LSA of cylinder = 280π

LSA of cylinder = 280π2πrh =280π

LSA of cylinder = 280π2πrh =280π2×22/7 ×14× h. =280 × 22/7

LSA of cylinder = 280π2πrh =280π2×22/7 ×14× h. =280 × 22/788h. = 40×20

LSA of cylinder = 280π2πrh =280π2×22/7 ×14× h. =280 × 22/788h. = 40×20 h. = 40×20/88

LSA of cylinder = 280π2πrh =280π2×22/7 ×14× h. =280 × 22/788h. = 40×20 h. = 40×20/88 h. =10

Now,

volume. = π r square h

volume. = π r square h = π × 14× 14 × 10

volume. = π r square h = π × 14× 14 × 10 = 1960π