Question

In a cylindrical vessel of radius 10cm containing some water, 9000 small spherical balls are dropped which are completely immersed in water which raises the water level. The radius of each spherical ball is 0.5cm then find the rise in the level of water

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given In a cylindrical vessel of radius 10 cm containing some water, 9000 small spherical balls are dropped which are completely immersed in water which raises the water level. The radius of each spherical ball is 0.5 cm then find the rise in the level of water

• Let R be the radius of cylinder and h be the height of cylinder and r be the radius of sphere.
• Let n be the number of spherical balls that are dropped in a cylindrical vessel.
• So volume of water is increasing in cylinder.So we need to find the level of rise of water level in the vessel.
• R = 10 cm, r = 0.5 cm
• So n = volume of water displaced / volume of one spherical ball
• Therefore n = volume of water displaced / volume of one spherical ball
• So n = πR^2h/ 4/3 πr^3
•        = 3 R^2h / 4r^3
• Or h = 4 x 9000 x (0.5)^3 / 3 x 10^2
• Or h = 9000 x 4 x 0.125 / 300
• Or h = 15 cm  

Reference link will be

https://brainly.in/question/15919300