Question

In a cylindrical water tank the hieght is 24cm & base diameter is 7cm find the Volume of the water tank can store water in leters​

Answer 1

✨Answer:✨

☞Volume of Cylinder (in Litres ) = 0.924 Litres

✨Given:✨

$\\☞\tt Height \:of\: Cylinder\: =\: 24 \:cm$

$☞\tt Diameter\: of \:base\: of \:Cylinder \:=\: 7 \:cm$

✨Concept:✨

• Volume of Cylinder = $\pi r^2 h$
• Diameter = 2 * radius
• 1 Litres = 1000 $cm^3$

✨To Find:✨

Volume of cylinder with above given information in litres

✨Explanation:✨

We know that,

☞Diameter = 2 * radius

☞Radius = $\dfrac{Diameter}{2}$

Given,

Diameter = 7 cm

Radius = $\dfrac{7}{2}$ cm

Radius = 3.5 cm

Substituting the given values:

Volume = $\dfrac{22}{7}\times3.5\times3.5\times24\: cm^3$

Volume = $22\times0.5\times3.5\times24\:cm^3$

Volume = $11\times84\:cm^3$

Volume = 924 $cm^3$

We know that,

1 Litres = 1000 $cm^3$

1 $cm^3=\dfrac{1}{1000}\:Litres$

$\therefore\:924\:cm^3\:=\:0.924\:Litres$

Therefore, the answer is 0.924 $cm^3$

✨Other Formulas of

Cylinder:✨

Lateral Surface Area= 2πrh

Total Surface Area = 2πr(h + r)

⭐Formulas of Hollow Cylinder:⭐

Let the external radius , internal radius and height of a hollow cylinder be R , r and h respectively.

• Thickness of Hollow Cylinder = R-r

• Area of cross section = $\pi (R^2-r^2)$

• External Curved Surface Area = 2πRh

• Internal Curved Surface Area = 2πrh

• Total Surface Area = external curved surface area + internal curved surface area + area of two ends

$\:\:\:\:\:\:\:\:\:$= 2πRh + 2πrh + 2π($R^2-r^2$)

$\:\:\:\:\:\:\:\:\:$= 2π(Rh + rh + $R^2-r^2$)

• Volume of material used = π$R^2$h - π$r^2$h

$\:\:\:\:\:\:\:\:\:$= πh($R^2-r^2$)

Answer 2

Answer:

Answer:✨

\begin{gathered}\\\end{gathered}

☞Volume of Cylinder (in Litres ) = 0.924 Litres

\begin{gathered}\\\\\end{gathered}

✨Given:✨

\begin{gathered}\\☞\tt Height \:of\: Cylinder\: =\: 24 \:cm\end{gathered}

☞HeightofCylinder=24cm

☞\tt Diameter\: of \:base\: of \:Cylinder \:=\: 7 \:cm☞DiameterofbaseofCylinder=7cm

\begin{gathered}\\\\\end{gathered}

Concept:✨

\begin{gathered}\\\end{gathered}

Volume of Cylinder = \pi r^2 hπr

2

h

Diameter = 2 * radius

1 Litres = 1000 cm^3cm

3

\begin{gathered}\\\\\end{gathered}

✨To Find:✨

\begin{gathered}\\\end{gathered}

Volume of cylinder with above given information in litres

\begin{gathered}\\\\\end{gathered}

Explanation:✨

\begin{gathered}\\\end{gathered}

We know that,

☞Diameter = 2 * radius

☞Radius = \begin{gathered}\dfrac{Diameter}{2}\\\end{gathered}

2

Diameter

Given,

Diameter = 7 cm

Radius = \dfrac{7}{2}

2

7

cm

Radius = 3.5 cm

\begin{gathered}\\\end{gathered}

Substituting the given values:

\begin{gathered}\\\end{gathered}

Volume = \dfrac{22}{7}\times3.5\times3.5\times24\: cm^3

7

22

×3.5×3.5×24cm

3

Volume = 22\times0.5\times3.5\times24\:cm^322×0.5×3.5×24cm

3

Volume = 11\times84\:cm^311×84cm

3

Volume = 924 cm^3cm

3

Litres = 1000 cm^3cm

3

1 cm^3=\dfrac{1}{1000}\:Litrescm

3

=

1000

1

Litres

\therefore\:924\:cm^3\:=\:0.924\:Litres∴924cm

3

=0.924Litres

Therefore, the answer is 0.924 cm^3cm

3

\begin{gathered}\\\\\end{gathered}

Other Formulas of

Cylinder:✨

\begin{gathered}\\\end{gathered}

Lateral Surface Area= 2πrh

Total Surface Area = 2πr(h + r)

\begin{gathered}\\\\\end{gathered}

⭐Formulas of Hollow Cylinder:⭐

\begin{gathered}\\\end{gathered}

Let the external radius , internal radius and height of a hollow cylinder be R , r and h respectively.

\begin{gathered}\\\end{gathered}

Thickness of Hollow Cylinder = R-r

\begin{gathered}\\\end{gathered}

Area of cross section = \pi (R^2-r^2)π(R

2

−r

2

)

\begin{gathered}\\\end{gathered}

External Curved Surface Area = 2πRh

Internal Curved Surface Area = 2πrh

\begin{gathered}\\\end{gathered}

Total Surface Area = external curved surface area + internal curved surface area + area of two ends

\:\:\:\:\:\:\:\:\: = 2πRh + 2πrh + 2π(R^2-r^2R

2

−r

2

)

\:\:\:\:\:\:\:\:\: = 2π(Rh + rh + R^2-r^2R

2

−r

2

)

\begin{gathered}\\\end{gathered}

Volume of material used = πR^2R

2

h - πr^2r

2

h

\:\:\:\:\:\:\:\:\: = πh(R^2-r^2R

2

−r

2

)

\begin{gathered}\\\\\end{gathered}