Math, asked by pavi1305, 23 days ago

In a dairy farm, 40 cows eat 40 bags of husk
in 40 days. In how many days one cow will eat one
bag of husk?​

Answers

Answered by nimishthegreat2007
3

Answer:

0.025.

Step-by-step explanation:

40 cows eat 40 bags of husk in 40 days.

This means, 1 bag of husk is consumed daily.

:. 1 cow eats 1÷40 = 0.025.

Answered by Diabolical
4

Answer:

The answer will be 40 days.

Step-by-step explanation:

We have given;

total cows = 40;

total bags of husk = 40;

total days to eat husks = 40 days.

Here,

If we will increase cows, no. of bags will increase too because they will eat more.

Hence, C ∝B. (i)

where, C = no. of cows;

and, B = bags of husks;

Now, if we will increase cows, the no. of days to eat the husks will decrease since they will eat more quickly than before.

Hence, C ∝1/D; (ii)

where, C = no. of cows;

and, D = days to eat husks;

So, combine eq. (i) and (ii);

Hence, C ∝ B/D;

C = K (B/D); (here, K is some constant)

Now, put the values in this equation;

Thus, 40 = K (40/40);

K = 40. (iii)

Now, we are asked for the days required by a cow to eat one bag of husk.

So, C = 1;

B = 1;

K = 40; (from eq. (iii))

Now of days required will be;

C = K (B/D);

1 = 40 (1/D);

D = 40.

No. of days taken by a cow to eat one bag of husk is 40.

That's all.

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