Question

In a dam, generating hydro-electric
power, waterfalls at a rate of
1000 kg/sec from a height of 100 m.
Assuming that 60% of the energy of
falling water is converted to electrical
energy, calculate the energy generated
per second. (g=9.8 m/s2).​

Answer 1

Answer:

falling water is converted to electrical energy

Answer 2

Answer:

Given,

mass = 1000 kg

h = 100m

g = 9.8m/s^ 2

we know that,

KE = PE (at ground position)

therefore -

total KE = mgh = 1000×100×9.8

= 980000j

= 980 kj

Then,

60% of KE = 60/100×980 kj

= 3/5×980kj

= 3×196kj

=588 kj